Respuesta :
Answer:
[tex]\frac{4}{\sqrt{7}}-1+\frac{2}{\sqrt{7}}+1[/tex]
[tex]=\frac{4}{\sqrt{7}}+\frac{2}{\sqrt{7}}-1+1[/tex]
[tex]\frac{4}{\sqrt{7}}+\frac{2}{\sqrt{7}}=\frac{6\sqrt{7}}{7}[/tex]
[tex]\frac{6\sqrt{7}}{7}-1+1[/tex]
[tex]-1+1=0[/tex]
[tex]=\frac{6\sqrt{7}}{7}[/tex]
OAmalOHopeO
Answer:
Answer is (6[tex]\sqrt{7}[/tex] +2)/6
Step-by-step explanation:
The question isn't very clear, so I'm gonna assume the denominator is [tex]\sqrt{7}[/tex]-1 and [tex]\sqrt{7}[/tex]+1
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