Question

The elevator of a large building is to raise a net mass of 400 kg at a constant speed of 12 m/s using an electric motor. minimum power rating of the motor should be

Answer 1

P =Force*velocity
   =mass*acceleration due to gravity*velocity
   =(400kg)(9.81m/s²)(12m/s)
   =47088W or 4.7*10⁴W

Answer 2

Answer:

$P=47.040 \ kW$

Explanation:

In the question given things are:

Total mass of elevator, $m=400\ kg$.

It is also given that it moves with constant speed, $v=12\ m/s$.

So, power for object moving in constant velocity is given as.

$P=m \times g \times v$.

Putting all values in above equation.

$P=400\times 9.8 \times 12=47040 \ W=47.040 \ kW$.

Hence, it is the required solution.