Question

What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?

Answer 1

Molar mass CaCl₂ = 110.98 g/mol

number of moles :

n = m / molar mass

n = 330 / 110.98

n =2,9735 moles

Molarity ( M ) = moles solute / liters solution

M = 2.9735 / 1

M = 2.9735 mol/L⁻¹

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