Question

Rank the following in order of increasing mass: 1.0 mole of SF4, 0.50 mole of H2S, 0.20 mole of Cu, and 0.10 mole of Pb.
a. SF4, H2S, Cu, Pb
b. Pb, Cu, H2S, SF4
c. Pb, Cu, SF4, H2S
d. H2S, SF4, Cu, Pb

Answer 1

Answer:

the correct answer is:

c. Pb, Cu, SF4, H2S

Explanation:

To rank the substances in order of increasing mass, we need to consider the molar masses of each substance and then multiply by the number of moles given.

The molar masses (in g/mol) of the substances are approximately:

- SF₄: 32.07 + 4 × 19.00 = 108.07 g/mol

- H₂S: 2 × 1.01 + 32.07 = 34.09 g/mol

- Cu: 63.55 g/mol

- Pb: 207.2 g/mol

Now, let's calculate the masses:

1.0 mole of SF₄: 1.0 mol × 108.07 g/mol = 108.07 g

0.50 mole of H₂S: 0.50 mol × 34.09 g/mol = 17.045 g

0.20 mole of Cu: 0.20 mol × 63.55 g/mol = 12.71 g

0.10 mole of Pb: 0.10 mol × 207.2 g/mol = 20.72 g

Now, let's arrange them in increasing order of mass:

1. Cu (12.71 g)

2. H₂S (17.045 g)

3. Pb (20.72 g)

4. SF₄ (108.07 g)

Therefore, the correct answer is:

c. Pb, Cu, SF4, H2S