Answer:
192 VIP tickets
3888 ground tickets
Step-by-step explanation:
VIP tickets
The dimensions of the two congruent VIP sections are 4 yards × 24 yards. Given that each chair requires a square of 1 yard × 1 yard, the number of chairs in the VIP area is:
[tex]\textsf{One VIP area}=4 \times 24 = 96\; \textsf{chairs}\\\\\textsf{Two VIP areas}=96 \times 2 = 192\; \sf chairs[/tex]
Therefore, 192 VIP tickets could be sold.
[tex]\dotfill[/tex]
Ground tickets
Given that the field is 53 yards wide, and there is one 5-yard aisle between the two congruent floor sections along the width of the field, the width of each congruent floor section is:
[tex]\dfrac{53-5}{2}=24\; \sf yards\;width[/tex]
Given that the field is 120 yards long, the stage takes up the first 20 yards, the VIP areas take up the next 4 yards and there are three 5 yard wide aisles along the length of the field, the length of each congruent floor section is:
[tex]\dfrac{120-20-4-(3 \times 5)}{3}=\dfrac{96-15}{3}=\dfrac{81}{3}=27\; \sf yards\;length[/tex]
Therefore, the dimensions of each of the six congruent floor sections is 24 yards × 27 yards. Given that each chair requires a square of 1 yard × 1 yard, the number of chairs in the floor area is:
[tex]\textsf{One floor section}=24 \times 27 =648\;\textsf{chairs}\\\\\textsf{Six floor sections}=648 \times 6 = 3888\; \sf chairs[/tex]
Therefore, 3888 ground tickets could be sold.
