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Answer: The midpoint of line segment AB is,

[tex](4,3)[/tex]

Step-by-step explanation:

Since, the coordinates of the midpoint of a line segment having the endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are,

[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

Thus, the coordinates of midpoint of the line segment AB having endpoints A(9, 8) and B(-1, -2) are,

[tex](\frac{9+(-1)}{2},\frac{8+(-2)}{2})[/tex]

[tex]=(\frac{9-1}{2}, \frac{8-2}{2})[/tex]

[tex]=(\frac{8}{2}, \frac{6}{2})[/tex]

[tex]=(4,3)[/tex]

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