Answer: The midpoint of line segment AB is,
[tex](4,3)[/tex]
Step-by-step explanation:
Since, the coordinates of the midpoint of a line segment having the endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are,
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
Thus, the coordinates of midpoint of the line segment AB having endpoints A(9, 8) and B(-1, -2) are,
[tex](\frac{9+(-1)}{2},\frac{8+(-2)}{2})[/tex]
[tex]=(\frac{9-1}{2}, \frac{8-2}{2})[/tex]
[tex]=(\frac{8}{2}, \frac{6}{2})[/tex]
[tex]=(4,3)[/tex]