The problem is asking for the height of the building given an angle of elevation and a distance. This is a trigonometry problem where we can use the tangent of the angle, which is the ratio of the opposite side (height of the building) to the adjacent side (distance from the building).
Given:
Angle of elevation, theta = 30 degrees
Distance from the building, b = 10 root 3 meters
We know that tan(theta) = opposite/adjacent, so we can set up the equation:
tan(30 degrees) = h / (10 root 3)
Solving for h (height of the building), we get:
h = 10 root 3 * tan(30 degrees)
Since tan(30 degrees) = 1/root 3, the height of the building is:
h = 10 root 3 * (1/root 3) = 10 meters
So, the building is approximately 10 meters tall. Please note that this is an approximation and the actual height may vary slightly due to rounding or measurement errors.
