Question

A line passes through the point (-9, -6) and has a slope of -4/3. Write an equation in slope-intercept form for this line.

Answer 1

Answer:

y = - $\frac{4}{3}$ x - 18

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given slope m = - $\frac{4}{3}$ , then

y = - $\frac{4}{3}$ x + c ← is the partial equation

to find c, substitute (- 9, - 6 ) for x and y in the partial equation

- 6 = - $\frac{4}{3}$ (- 9) + c = 12 + c ( subtract 12 from both sides )

- 18 = c

y = - $\frac{4}{3}$ x - 18 ← equation of line