Find the value of n in the solution to the system of equations shown.

[tex] \bf \begin{cases}
\boxed{m}=5n-3\\
m=3n+7
\end{cases}\implies \boxed{5n-3}=3n+7\implies 2n=10
\\\\\\
n=\cfrac{10}{2}\implies n=5 [/tex]
Subtract the second equation from the first.
... 0 = 2n -10
Divide by the coefficient of n.
... 0 = n - 5
Add 5.
... 5 = n . . . . the lower-left selection is appropriate