Question

when the pressure that a gas exerts on a sealed container changes from blank torr to 900 torr the temperature changes from 300 k to 450 k

Answer 1

It's 600 torr, just use Gay-Lussac's law P1/T1=P2/T2

Answer 2

Answer:

Initial pressure = 600 torr

Explanation:

Given:

Initial pressure, P1 = 900 torr

Initial Temperature, T1 = 300 K

Final temperature, T2 = 450 K

To determine:

Final pressure of  gas, P2

Explanation:

Based on the ideal gas equation

$PV = nRT$

where n = moles of gas

R = gas constant, T = temperature

At constant volume (V), the above equation becomes:

P/T = constant

This is Gay-Lussac's law

$\frac{P1}{T1} =\frac{P2}{T2} \\\\P1=\frac{P2}{T2} *T1=\frac{900\ torr}{450\ K} *300\ K=600\ torr$