Question

Find the 2nd term of an arithmetic sequence with t1 = 4 and t5 = 6.

11/2

5

9/2

4

Answer 1

tn = t1 + (n-1)*d, so t5 = t1 + 4*d, then d = (t5 -t1)/4 = 1/2,

Then t2 = t1 + d = 4+1/2 = 9/2=4.5, so The third one!