First find the value or (DEA)
For this you will have to use the Pythagorean theory,
[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]
C is mainly the hypotenuse,
Meaning you either want to find A or B,
Since the hypotenuse has two segments, both values are 10, then just add them together making it 20,
Then 16 will be A or B, in this case it will be A,
To find a you must first move A to the other side by doing the opposite,
[tex] {b}^{2} = {c}^{2} - {a}^{2} [/tex]
Now plug in the values,
[tex] {b}^{2} = {20}^{2} - {16}^{2} [/tex]
[tex] {b}^{2} = 400 - 256[/tex]
[tex] {b}^{2} = 144[/tex]
Now just find the square root of both factors,
[tex] \sqrt{ {b}^{2} } = \sqrt{12} [/tex]
The value of (DEA) is,
[tex]b = 12[/tex]
Now we want to find (d)
Since 12 is the value of the base, then divide it 2 to find (DE), after just repeat the whole process but with the value of hypotenuse 10 instead of 20 since we want to find the smaller triangle,
[tex] {a}^{2} = {c}^{2} - {b}^{2} [/tex]
Now plug in the value
[tex] {a}^{2} = {10}^{2} - {6}^{2} [/tex]
[tex] {a}^{2} = 100 - 36[/tex]
[tex] {a}^{2} = 64[/tex]
Now find the square root of both factors,
[tex] \sqrt{ {a}^{2} } = \sqrt{64} [/tex]
[tex]a = 8[/tex]
The value of (d) is (8)
Hope this helped
:D