Question

You roll a six sided die and toss a coin. What is the probability of rolling an odd number and then getting heads?

Answer 1

P(O,T)=(3/6)(1/2)

P(O,T)=1/4

Answer 2

Hello there! Thank you for asking your question here at Brainly! I will be assisting you with answering your question, and will teach you how to tackle it on your own in the future.

So, let's take a look at our question.
"You roll a six sided die and toss a coin. What is the probability of rolling an odd number and then getting heads?"

First, we need to understand what we're dealing with, and how to handle it.
Let's tackle these individually, rather than doing it all at once and getting confused/stuck.
We roll a six sided die, which is numbered from 1 to 6. "What is the probability of rolling an odd number?"
Well, let's count how many odd numbers there are from 1 to 6.
1, 3, 5; We have three odd numbers on our six sided die.
Let's set that up as a fraction, $\frac{3}{6}$
However, we can simplify it into simpler terms - divide both numbers by 3.
3/3 = 1
6/3 = 2
We now have our simplified fraction, $\frac{1}{2}$

Now, let's focus on the other half of the problem.
"You flip a coin. What's the probability of landing on heads?"
Well, a coin only has two sides - heads and tails - which means we have 1/2 chances of landing on heads or tails generally.

Since the question asks for the probability of an odd number and landing on heads, we need to multiply our fractions.

We have these two fractions:
$\frac{1}{2}$ * $\frac{1}{2}$
Multiply them.
$\frac{1}{2}$ * $\frac{1}{2}$ = $\frac{1}{4}$

Your answer is $\frac{1}{4}$

I hope this helps!