Respuesta :

BD=DC=[tex] \sqrt{1+1} [/tex]=[tex] \sqrt{2} [/tex]
BC=[tex] \sqrt{BD+DC} [/tex]=2

Answer:

Option 3rd is correct.

Step-by-step explanation:

Given: AB = AD = 1 unit   and BD = CD

We have to find, CB

In ΔABD,

using Pythagoras theorem

BD² = AB² + AD²

BD² = 1² + 1²

BD = ± √2

BD = √2   (length can not be negative)

CD = BD = √2

Again using Pythagoras theorem in ΔBDC

CB² = BD² + CD²

CB² = (√2)² + (√2)²

CB² = 2 + 2

CB² = 4

CB = 2

Therefore, Option 3rd is correct.

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