Question

What is the positive root of the equation x 2 + 5x = 150?

Answer 1

Move the 150 to the left to get x^2+5x-150=0
Then factor to (x+15)(x-10)=0
The roots are -15 and 10
The positive root is 10

Answer 2

The positive root of the given quadratic function is x = 10.

How to solve the quadratic function?

We have the equation:

$x^2 + 5x = 150$

First, we rewrite it as:

$x^2 + 5x - 150 = 0$

Using the Bhaskara's formula, we will get:

$x = \frac{-5 \pm \sqrt{5^2 - 4*(-150)*1} }{2} \\\\x = \frac{-5 \pm 25 }{2}$

The positive solution is:

x = (-5 + 25)/2 = 10

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