Question

What is the standard form equation of the line shown below?

Answer 1

Since no one gives brainliest for actually showing their work...

The slope is -1/3
The Y intercept is 4 2/3

SlopeY is Y = -1/3x + 4 2/3

Change to standard form

Y = -1/3x + 4 2/3
0 = -1/3x + 4 2/3 - Y
(-3)    (-3)      (-3)    (-3)
-3 = -x - 8 + 3Y
5 = x - 3y

So the answer is 5 = x - 3y and I have no idea if that's correct.

Answer 2

Answer:

$y=-\frac{1}{3}x$ + $4\frac{2}{3}$

Step-by-step explanation:

Standard form of straight line equation is: y = bx + c

From the graph, the following conditions can be found:

• y=5 for x=-1
• y=4 for x=2

Substitution:

Substitute first set of conditions into equation to find c in terms of b:

5 = b(-1) + c

5 = c - b

c = 5+b

Substitute second set of conditions, and c into equation to find b:

4 = b(2) + c

4 = 2b +(5+b)

4 = 3b +5

-1 = 3b

∴ b = - $\frac{1}{3}$

Substitute b into c:

c = 5 + (- $\frac{1}{3}$)

∴ c = $4\frac{2}{3}$

Substitute b and c into line equation:

$y=-\frac{1}{3}x$ + $4\frac{2}{3}$