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29-06-2017
Mathematics

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How do you find the solution set for -x^2+6x<0?

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konrad509 konrad509

29-06-2017

[tex]-x^2+6x\ \textless \ 0\\ -x(x-6)\ \textless \ 0\\ x\in(-\infty,0)\cup(6,\infty) [/tex]

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