Question

What is the solution to 2x^2+8x=x2-16? x=4, x=-2, x=2, x=4​

Answer 1

Answer:

x=-4

Step-by-step explanation:

Given:

2x^2+8x=x2-16

2x^2-x^2+8x+16=0

x^2+8x+16=0

As per the formula (a+b)^2= a^2 +2ab +b^2

x^2+2(4)x+(4)^2=0

(x+4)^2=0

x+4=0

x=-4!

Answer 2

Answer:

x=-4

Step-by-step explanation:

Hello,

thanks for leaving your query here in brainly. I think I can help you with this

$2x^{2} +8x=x^{2} -16\\organizing\ the\ terms\\2x^{2} +8x-x^{2}+16=0\\x^{2}+8x+16=0$

this can be factorized as

$x^{2}+8x+16\\a^{2}  +2ab+b^{2}=(a+b)^{2}\\ x^{2}+8x+16=(x+4)^{2}$

hence

$(x+4)^{2}=0\\now, isolate\ x\\\\\sqrt[]{(x+4)^{2}} =\sqrt{0}\\ x+4=0\\x=-4$

I hope it helps, Have a nice day.