A box contains 20 cards numbered 1–20. You select a card. Without replacing the first card, you select a second card. Find P(1, then 20).

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Answer:

1/380

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = expected outcome of event/Total outcome.

Since the box contains 20 cards, the total outcome is 20.

If a card is first selected from the total card, the probability of selecting the card will be 1/20.

Since the card isn't replaced after selecting, the total card remaining will be 19, which will be our new total outcome.

If the second card is selected, the probability of selecting the second card will be 1/19.

Probability of selecting the first and then the second will give:

1/20×1/19

= 1/380

The value of the probability P(1, then 20) is 0.00263

The probability P(1, then 20) implies that, we calculate the probability of selecting 1 and then 20

This is calculated as:

P(1, then 20). = P(1) * P(20, provided that 1 has been selected)

The selection is without replacement.

So, we have:

P(1, then 20) = 1/20 * 1/19

Evaluate the product

P(1, then 20) = 0.00263

Hence, the value of the probability P(1, then 20) is 0.00263

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