Question

8. Make a rule: If the acceleration is constant and the starting velocity is zero, what is the relationship between the acceleration of a falling body (a), the time it takes to fall (t), and its instantaneous velocity when it hits the ground (v)?

Answer 1

In a uniform accelerated motion, the velocity at time t is given by:

$v(t)=v_0 +at$

where

$v_0$ is the initial velocity

a is the acceleration

t is the time

In this problem, we are told that the starting velocity of the body is zero ($v_0=0$), so we can rewrite the previous equation as

$v(t)=at$

and if we take t as the time the body takes to hits the ground, this relationship gives us the velocity of the body when it hits the ground.

Answer 2

Answer:

The relationship between acceleration, velocity and time is $v(t)=at$.

Explanation:

As per the Newton's first law of motion.

$v(t)=v_{0}+at$

Here,

Velocity at time $t$ is $v(t)$

Initial velocity is $v_{0}$

Acceleration is $a$

Time is $t$

The initial velocity is zero. Put the $0$ for $v_{0}$ in above equation.

$v(t)=0+at\\v(t)=at$

Thus, the acceleration of a falling body (a), the time it takes to fall (t), and its instantaneous velocity when it hits the ground (v) is $v(t)=at$.

Learn more about Law of motion here:

https://brainly.com/question/19657850