Question

How many moles of hexane must burn to form 18.4 mol of carbon dioxide

Answer 1

he combustion reaction of hexane:

2 C6H14 + 19 O2 = 12 CO2 + 14 H2O

2 mol C6H14 ---------> 12 mol CO2
x mol C6H14 ---------> 18.4 mol CO2

12 * x = 18.4 * 2

12 x = 36.8

x = 36.8 / 12

x = 3.067 moles of CO2

hope this helps!.

Answer 2

Answer : The number of moles of hexane is, 3.06 moles

Explanation : Given,

Moles of carbon dioxide = 18.4 mole

The balanced chemical reaction will be,

$2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O$

From the balanced chemical reaction, we conclude that 2 moles of hexane react with 19 moles of oxygen gas to give 12 moles of carbon dioxide gas and 14 moles of water as a product.

As, 12 moles of carbon dioxide obtained from 2 moles of hexane

So, 18.4 moles of carbon dioxide obtained from $\frac{2}{12}\times 18.4=3.06$ moles of hexane

Therefore, the number of moles of hexane is, 3.06 moles