Question

What is the area of this triangle?
a) a=1/2(y3-y2)(x3-x1)
B) a=1/2(y3-y1)(x3-x1)
C) a=1/2(y2-y1)(x3-x1)

Answer 1

The area of a triangle is:

A=hb/2 where h=height and b=base

We can let the "height" be the horizontal magnitude, (x3-x1)

And the base would then be the vertical magnitude, (y2-y1)

So the area is:

A=(1/2)(y2-y1)(x3-x1)

Answer 2

Answer:

D. A = $\frac{1}{2} (y_{2} -y_{1} )(x_{3} -x_{1} )$

Step-by-step explanation:

This was correct on plato:)