Respuesta :
i think it is D, since
P = 2(l + b)
÷2
P/2 = l + b
- l
P/2 - l = b
which can be rearranged by multiplying by 2
which gets you
(P - 2l) = 2b
÷ 2 again
then you get
1/2 (P -2l) = b
P = 2(l + b)
÷2
P/2 = l + b
- l
P/2 - l = b
which can be rearranged by multiplying by 2
which gets you
(P - 2l) = 2b
÷ 2 again
then you get
1/2 (P -2l) = b
Answer:
Option (d) is correct.
[tex]b=\frac{1}{2}(P-2l)[/tex]
Step-by-step explanation:
Given : Formula P = 2( l + b )
We have to rearrange the given formula for b.
Consider the given formula
P = 2(l +b)
Divide both side by 2, we have,
[tex]\frac{P}{2}=l+b[/tex]
Now, subtract l both side, we hvae,
[tex]\frac{P}{2}-l=l+b-l[/tex]
Simplify, we have,
[tex]\frac{P}{2}-l=b[/tex]
Taking lcm, we have,
[tex]\frac{P-2l}{2}=b[/tex]
Thus, [tex]b=\frac{1}{2}(P-2l)[/tex]
Option (d) is correct.