Question

Which linear inequality could represent the given table of values?
y < –2x + 3
y ≤ –2x + 3
y > –x – 3
y ≤ –x – 3

Answer 1

Answer: The answer is (B) y ≤ –2x + 3 .

Step-by-step explanation: We are to select the correct linear inequality that could represent the table of values given in the question.

If (x, y) = (-4, -1), then

$y=-1,\\\\-2x+3=-2\times(-4)+3=8+3=11.$

So, y < -2x + 3.

If (x, y) = (-2, 4), then

$y=4,\\\\-2x+3=-2\times(-2)+3=4+3=7.$

So, y < -2x + 3.

If (x, y) = (3, -3), then

$y=-3,\\\\-2x+3=-2\times 3+3=-6+3=-3.$

So, y = -2x + 3.

If (x, y) = (3, -4), then

$y=-4,\\\\-2x+3=-2\times 3+3=-6+3=-3.$

So, y < -2x + 3.

Therefore, we have y is either less than or equal to (-2x + 3).

Thus, y ≤ –2x + 3  and (B) is the correct option.

Answer 2

Answer:

b

Step-by-step explanation: