Question

How many milliliters of 2.00 m h2so4 are needed to provide 0.250 mole of h2so4?

Answer 1

Given: 2.00 m h2so4 / L
            0.250 moles
Solve
To get the volume we need to divide 0.250 moles from 2.00 moles / L 

Volume = (0.250 moles) 
                -----------------------
                 (2.00 moles/L)

                  
              = 0.125 L x 100
              = 125 ml

So the answer is 125 milliliters of 2.00 m h2so4 are necessary to provide 0.250 mole of it. 
 
 

Answer 2

Answer:

125 ml of 2.00 M solution of sulfuric acid will give 0.250 moles of sulfuric acid.

Explanation:

$Molarity=\frac{\text{Mass of compound}}{\text{Molar mass of compound}\times \text{volume of solution (L)}}=\frac{\text{Moles of compound}}{\text{Volume of the solution} (L)}$

Volume of the sulfuric acid solution = V

Moles of sulfuric acid = 0.250 moles

Molarity of the sulfuric acid solution = 2.00 M

$2.00 M=\frac{0.250 moles}{V}$

V = 0.125 L = 125 mL

125 ml of 2.00 M solution of sulfuric acid will give 0.250 moles of sulfuric acid.