Respuesta :
Step 1
Find the volume of the tank
we know that
the volume of the sphere is equal to
[tex]V=\frac{4}{3} \pi r^{3}[/tex]
where
r is the radius of the sphere
we have
[tex]r=6\ yd[/tex]
substitute in the formula
[tex]V=\frac{4}{3} \pi 6^{3}=904.32\ yd^{3}[/tex]
Step 2
Find the cost of the liquid
we know that
the cost of the liquid is [tex]7.15\frac{\$}{yd^{3}}[/tex]
so
Multiply by the volume to obtain the total value of the liquid
[tex]904.32\ yd^{3}*7.15\frac{\$}{yd^{3}}=\$6,465.89[/tex]
therefore
the answer is
the total value of the liquid in the tank is [tex]\$6,465.89[/tex]
Answer:
Total value is $ 6465.89.
Step-by-step explanation:
Since, the volume of a sphere is,
[tex]V=\frac{4}{3}\pi(r)^3[/tex]
Where, r is the radius of the sphere,
Here, the tank is of spherical shape having radius, r = 6 yards,
So, the volume of the tank is,
[tex]V=\frac{4}{3}\pi (6)^3[/tex]
Since, [tex]\pi = 3.14[/tex]
[tex]\implies V=\frac{4}{3}\times 3.14\times 216=\frac{2712.96}{3}=904.32\text{ cube yards}[/tex]
Now, given,
The liquid in the tank costs $ 7.15 per cubic yards,
Hence, the total cost of the liquid in the given tank = cost of liquid cost per cubic yards × Volume of the tank
= 7.15 × 904.32
= $ 6465.888 ≈ $ 6465.89