Question

Ohm's law is often used in conjunction with the P = IV equation. A small flashlight bulb provides a resistance of 7.0 Ω to the 400. mA current that runs through it. Determine the power generated from the circuit.

Answer 1

Answer:

P=1.12 W

Explanation:

We can use Ohm's law and the equation P=IV to determine the power generated from the circuit, which will eventually equate the power.

Ohm's law states that the current flowing through a conductor is directly proportional to the voltage across it and inversely proportional to the resistance. Mathematically, Ohm's law is represented as V=IR.

Given:

R=7.0 Ω

I= 400.0 mA => 0.4 A

(1) - Use Ohm's law to find the voltage

V=IR

=> V=(7.0 Ω)(0.4 A)

=> V=2.8 V

(2) - Now using the voltage we just found, we can use the power equation

P=IV

=> P=(0.4 A)(2.8 V)

=> P=1.12 W

Thus, the problem is solved.