Answer:
The answer to your question is Final temperature = 135.2 °F
Step-by-step explanation:
Data
Initial temperature = T₀ = 192.7°F
Rate of decreasement = 2.3°F x t
Final temperature = T₂ = ?
Final time = t₂ = 25 min
Process
1.- Write an equation
T₂ = T₀ - 2.3 t₂
2.- Substitute values given in the formula
T₂ = 192.7 - (2.3 x 25)
3.- Simplify and result
T₂ = 192.7 - 57.5
T₂ = 135.2 °F
Answer:the temperature of the soup after 25 minutes is 137.5 degrees
Step-by-step explanation:
As it cools, the temperature of the soup decreases 2.3 degrees F per minute. This is a linear rate. The rate at which the temperature is decreasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = 192.7 degrees
d = - 2.3 degrees (it is decreasing)
n = 25
We want to determine the value if the 25th term, T25. Therefore,
T25 = 192.7 -2.3 (25 - 1) = 192.7 - 2.3×24
T25 = 137.5 degrees
