Hello:
2x+3y=8
y =(-2/3)x+8/3 (the slope is : (-2/3) )
an equation of the line through (-1,4) and perpendicular to 2x+3y=8 is : y = ax+b
the slope is a : a×(-2/3) = -1......(
perpendicular to a line with a slope of -2/3)
a = 3/2 y=(3/2)x+b
the line that passes through (-1, 4) :4 =
(3/2)(-1)+b
b =11/2
the equation is : y = (3/2)x+11/2
