Answer:
D) [tex]2x^{3} +3x + 4[/tex].
Step-by-step explanation:
Given : quantity 6 times x to the 4th power plus 9 times x to the 2nd power plus 12 times x all over 3 times x.
To find : Simplify completely the quantity.
Solution : We have given that a statement .
According to question:
6 times x to the 4th power = [tex]6x^{4}[/tex].
9 times x to the 2nd power = [tex]9x^{2}[/tex].
12 times x = 12x.
[tex]6x^{4}[/tex] + [tex]9x^{2}[/tex] + 12x over 3x.
[tex]\frac{6x^{4}}{3x} +\frac{9x^{2}}{3x} +\frac{12x}{3x}[/tex].
On dividing we get ,
[tex]2x^{3} +3x + 4[/tex].
Therefore, D) [tex]2x^{3} +3x + 4[/tex].
