Respuesta :
(x-4i)(x+4i)=x^2+16
(x^2+16)(x-5)=x^3-5x^2+16x-80
Answer is B
(x^2+16)(x-5)=x^3-5x^2+16x-80
Answer is B
If a polynomial has roots 5, 4i and -4i, then it can has such three factors:
- [tex]x-5;[/tex]
- [tex]x-4i;[/tex]
- [tex]x-(-4i)=x+4i.[/tex]
Therefore, the expression for this polynomial is
[tex]f(x)=(x-5)(x-4i)(x+4i).[/tex]
Since
[tex](x-4i)(x+4i)=x^2-(4i)^2=x^2-16i^2=x^2-16\cdot (-1)=x^2+16,[/tex]
then
[tex]f(x)=(x-5)(x^2+16)=x^3-5x^2+16x-80.[/tex]
Answer: correct choice is B