Respuesta :
Answer:
The equation of the directrix of the parabola is [tex]y=5.5[/tex]
Step-by-step explanation:
we know that
The equation of a vertical parabola in standard form is equal to
[tex](x-h)^{2}=4a(y-k)[/tex]
where
(h,k) is the vertex of the parabola
y=k-a is the directrix of the parabola
In this problem we have
[tex]y=\frac{1}{2}x^{2}+6x+24[/tex]
Convert to standard form
[tex]y-24=\frac{1}{2}x^{2}+6x[/tex]
[tex]y-24=\frac{1}{2}(x^{2}+12x)[/tex]
[tex]y-24+18=\frac{1}{2}(x^{2}+12x+36)[/tex]
[tex]y-6=\frac{1}{2}(x^{2}+12x+36)[/tex]
[tex]y-6=\frac{1}{2}(x+6)^{2}[/tex]
therefore
[tex](x+6)^{2}=2(y-6)[/tex] ----> standard form
The vertex is the point (-6,6)
[tex]4a=2[/tex]
[tex]a=\frac{1}{2}=0.5[/tex]
The directrix of the parabola is
[tex]y=k-a[/tex]
[tex]y=6-0.5=5.5[/tex]
therefore
The equation of the directrix of the parabola is [tex]y=5.5[/tex]
Answer: y = 5.5
Just comfirm that the answer above is correct :)
