Question

The last problem on the paper

Answer 1

$\bf V=\pi r^2 h \\\\\\ \textit{now, we change "r" to }\frac{1}{3}r\to \frac{r}{3} \\\\\\ V=\pi \left( \frac{r}{3} \right)^2 h\implies V=\pi \cdot \cfrac{r^2}{3^2}\cdot h\implies V=\cfrac{\pi r^2 h}{9}$

the new tanks only hold 1/9 th of the original tanks only