The solution to the system of equations is (3, 6) and (-3, 18) after equating both the equations.
What is a quadratic equation?
Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]
We have a system of equation:
f(x) = x² - 2x + 3
f(x) = -2x + 12
Find a solution for the system of equations equates to the equations:
x² - 2x + 3 = -2x + 12
x² = 9
x = ±3
Plug the above values in the linear equation:
f(3) = 6
f(-3) = 18
(3, 6) and (-3, 18)
Thus, the solution to the system of equations is (3, 6) and (-3, 18) after equating both the equations.
Learn more about quadratic equations here:
brainly.com/question/2263981
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