Question

Calculate the grams of oxygen in 90.0 g of cl2o

Answer 1

Answer:

The correct answer is 16,576 g of $O_{2}$.

Explanation:

First, we must calculate the molar mass (Mm) of $O_{2}$ and $Cl_{2}O$.

Mm $O_{2}$= 32g

Mm $Cl_{2}O$ = 86,9 g

Now we know we have 90 g of $Cl_{2}O$, so let's find out how many moles of $Cl_{2}O$ there are in that amount.

90 g $Cl_{2}O$ * $\frac{1 mol Cl_{2}O}{86.9 g Cl_{2}O}$ = 1.036 mol $Cl_{2}O$

Now, in the $Cl_{2}O$ formation reaction we have that 1 mole of $O_{2}$ reacts to obtain 2 moles of $Cl_{2}O$:

$O_{2}$ + 2$Cl_{2}$ -> 2$Cl_{2}O$

Taking the coefficients, we calculate the number of moles of $O_{2}$ that react:

1,036 mol $Cl_{2}O$ * $\frac{1 mol O_{2}}{2 mol Cl_{2}O}$ = 0,518 mol $O_{2}$

Finally, we calculate the number of grams in the moles of $O_{2}$ that react:

0,518 mol $O_{2}$ * $\frac{32 g O_{2}}{1 mol O_{2}}$ = 16,576 g $O_{2}$

Have a nice day!

Answer 2

The mass of oxygen in 90.0 grams of the given compound is 16.6 g.

Molar mass of the given compound

The molar mass of the given compound is calculated as follows;

Cl₂O = (35.5 x 2) + 16 = 87 g/mol

The mass of oxygen in 90.0 grams of the given compound is calculated as follows;

87 g ----------- 16 g of oxygen

90 g ------------ ?

$= \frac{90 \times 16}{87} \\\\= 16.6 \ g$

Thus, the mass of oxygen in 90.0 grams of the given compound is 16.6 g.

Learn more about molar mass here: https://brainly.com/question/5610380