Answer:
x = 36
Step-by-step explanation:
You want to know how many more 3-digit codes can be made from odd numbers than from even numbers if 0 is excluded and no digit can be repeated.
The number of possible codes will be the product of the number of available digits for each position in the code.
There are 5 odd digits, so Ali has 5 available digits for the first position, 4 for the next, and 3 for the last. (Using a digit makes it unavailable for a different position.) Ali can make 5·4·3 = 60 codes
There are 4 even digits when 0 is excluded, so Mel has 4 available digits for the first position, 3 for the next, and 2 for the last. Mel can make 4·3·2 = 24 codes.
Ali can make x more codes than Mel, where ...
x = 60 -24 = 36