I am confused regarding the layout of the figure shown in this image. The distance between the two cross-sections is not uniform as it is 6 cm on one end and 8 cm on the other. My question is how would you solve it?
Please provide detailed steps and explanation.
Thanks in advance

I am confused regarding the layout of the figure shown in this image The distance between the two crosssections is not uniform as it is 6 cm on one end and 8 cm class=

Respuesta :

Answer:

  • volume: 240 cm³
  • area: 252 cm²

Step-by-step explanation:

You have a prism with a height of 8 cm and a cross section in the shape of a trapezium with bases 9 cm and 6 cm, and height 4 cm, and you want to know its volume and area.

Figure

We interpret the figure as  having an error in the placement of the "6 cm" dimension. We imagine it belongs next to the upper-right segment indicating the top edge is 3 cm shorter than the 9 cm bottom edge. Our understanding of the net for the figure is attached.

Volume

The area of each trapezium base is ...

  A = 1/2(b1 +b2)h

  A = 1/2(9 cm +6 cm)(4 cm) = 30 cm²

The distance between the bases is 8 cm, so the volume is ...

  V = Bh = (30 cm²)(8 cm) = 240 cm³ . . . . prism volume

Area

The attached net shows the lateral area to be that of a rectangle 8 cm wide and 4+9+5+6 = 24 cm long.

  lateral area = (8 cm)(24 cm) = 192 cm²

The area of one base was found above, so the area of both bases is ...

  total base area = 2 × 30 cm² = 60 cm²

Then the total surface area of the figure is ...

  TSA = LA +BA

  TSA = 192 cm² +60 cm² = 252 cm² . . . . total surface area

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Additional comment

The 6 cm top edge makes the slant length of 5 cm be the hypotenuse of a 3-4-5 right triangle. This supports our suspicion that the figure is mislabeled.

Ver imagen sqdancefan