Question

What is the standard form of the line that passes through (1, 1) and (3, 4)

Answer 1

the linear equation that passes through (1, 1) and (3, 4) in standard form is:

-3x + 2y = -1

What is the standard form of the line that passes through (1, 1) and (3, 4)?

First, let's write the line in the slope-intercept form.

Because the line passes through (1, 1) and (3, 4), we conclude that the slope will be:

a = (4 - 1)/(3 - 1) = 3/2

Then we have:

y = (3/2)*x + b

To find the value of b, we can use the point (1, 1), this means that:

1 = (3/2)*1 + b

1 = 3/2 + b

1 - 3/2 = b = -1/2

Then the linear equation is:

y = (3/2)*x - 1/2

Now we can multiply both sides by 2 so we get:

2y = 3x - 1

Subtracting 3x in both sides we get:

-3x + 2y = -1

That is the linear equation that passes through (1, 1) and (3, 4) in standard form.

If you want to learn more about linear equations:

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