Answer:
The answer is the option C
[tex]12\pi\ units^{2}[/tex]
Step-by-step explanation:
we know that
the circumference of a circle is equal to
[tex]C=2\pi r[/tex]
In this problem we have
[tex]C=4\pi\sqrt{3} \ units[/tex]
substitute in the equation and solve for r
[tex]4\pi\sqrt{3}=2\pi r[/tex]
[tex]2\sqrt{3}= r[/tex] -------> [tex]r=2\sqrt{3}\ units[/tex]
Find the area of the circle
Remember that
The area of a circle is equal to
[tex]A=\pi r^{2}[/tex]
substitute the value of r
[tex]A=\pi (2\sqrt{3})^{2}[/tex]
[tex]A=12\pi\ units^{2}[/tex]