Question

once the person gets half way around, they decide to simply let go of the merry-go-round to exit the ride. what is the magnitude of the linear velocity of the person right as they leave the merry-go-round?

Answer 1

The linear velocity during leaving merry-go-round is 1.25 m/s

We define the rate of change in position over a time period as velocity. Linear velocity is simply an object's velocity in a straight line, whereas Angular Velocity is how much an object spins, rotates, or turns.

The linear velocity during leaving merry- go-round is,

v' = w' x R

v' = 0.77 x 1.63

v' = 1.25 m/s

Hence, linear velocity during leaving merry-go-round is 1.25 m/s

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