The smallest possible value of c is 1 in this case.
If the integer a, b and c are in arithmetic progression.
Then we can write,
b = (a+c)/2
If the integer a, b and c are in geometric progression,
Then, we can write,
b = √(ac)
Now, we can write,
a+b = 2√(ac)
Squaring both sides,
a²+c²+2ac = 4ac
(a-c)² = 0
So,
a = c.
If a = c.
Then,
b = (a+a)/2
b = a
So, a = b = c.
Smallest possible positive integer is 1.
So, the smallest possible value of c is 1.
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