Question

how many moles of oxygen are required to react with 3.95 moles of c6h14, according to the following equation? (don’t forget to balance the equation first) c6h14(l) o2(g) → co2(g) h2o(l)

Answer 1

Moles of oxygen are required to react with 3.95 moles of C₆H₁₄, according to the following equation is

The balanced chemical equation is given as :

2C₆H₁₄   +   19O₂   ----->   12CO₂   +   14H₂O

given that :

moles of C₆H₁₄ = 3.95 mol

2 moles of C₆H₁₄ = 19 moles of O₂

moles of O₂ = ( 19 / 2 ) × 3.95

moles of O₂ = 9.5 × 3.95

moles of O₂ = 37.52 mol

The moles of O₂ = 37.52 mol

Thus, 3.95 moles of C₆H₁₄ , react with 37.52 mol of O₂  to produced carbon dioxide and the water.

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