Question

Write a balanced half-reaction for the reduction of solid manganese dioxide MnO2 to manganese ion Mn+2 in a basic aqueous solution. Be sure to add physical state symbols where appropriate

Answer 1

The unbalanced oxidation half-reaction is represented below:

$Mn^{2+}(aq)-- > MnO2(s)$

Balancing O in the aqueous medium, we get:

$Mn^{2+}(aq)+2H_{2}O(l)-- > MnO_{2}(s)$

Balancing H in an acidic medium, we get:

$Mn^{2+}(aq)+2H_{2}O(l)-- > MnO_{2}(s)+4H^{+}(aq)$

Balancing charge, we get:

$Mn^{2+}(aq)+2H_{2}O(l)-- > MnO_{2}(s)+4H^{+}(aq)+2^{e-}$

So, the balanced oxidation half-reaction is represented below:

$Mn^{2+}(aq)+2H_{2}O(l)-- > MnO_{2}(s)+4H^{+}(aq)+2^{e-}$

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