[tex]\bf u\implies \begin{cases} (14,-6)\\ (-4,7) \end{cases}\implies (-4-14)~,~(7-(-6)) \\\\\\ (-18) ~,~(7+6)\implies \stackrel{\textit{component form}}{\ \textless \ -18~,~13\ \textgreater \ } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ||u||=\sqrt{a^2+b^2}\implies ||u||=\sqrt{(-18)^2+13^2}\implies ||u||=\sqrt{493}[/tex]
Answers:
u = < -18, 13 >
|| u || ≈ 22.2 units.
Explanation:
Step 1: Subtract the initial points from the terminal points.
Initial points: ( 14 , -6 )
Terminal points: ( -4 , 7 )
u = ( -4 - 14 , 7 - ( -6 ) )
Step 2: Solve it. ( I suggest using a calculator )
-4 - 14 = -18
7 - ( -6 ) = 13
u = ( -18 , 13 )
The answers for the first two spaces are -18 and 13, but for the third space you need to the previous answers to solve it.
The formula required is u = [tex]\sqrt{(v)^2 + (u)^2 }[/tex]
The person above solved it correctly, but the only difference is that once you have [tex]\sqrt{493\\\\}[/tex], you need to solve it. Square root of 493 is 22.20360. Since the question says to round to the nearest tenth, it's 22.2.
I hope my explanation makes sense :)
