The FALSE condition for the given inequality 3(n−6)<2(n+12) is (D) S:{42}.
An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way.
The majority of the time, size comparisons between two numbers on the number line are made.
So, we have the inequality: 3(n − 6) < 2(n + 12)
Now, verify the false inequality as follows:
(A) S:{−5}
3(n − 6) < 2(n + 12)
3(-5 − 6) < 2(-5 + 12)
3(-11) < 2(7)
-33 < 14: TRUE
(B) S:{3}
3(n − 6) < 2(n + 12)
3(3 − 6) < 2(3 + 12)
3(-3) < 2(15)
-9 < 30: TRUE
(C) S:{12}
3(n − 6) < 2(n + 12)
3(12 − 6) < 2(12 + 12)
3(6) < 2(24)
18 < 48: TRUE
(D) S:{42}
3(n − 6) < 2(n + 12)
3(42 − 6) < 2(42 + 12)
3(36) < 2(54)
108 + 108: FALSE
Therefore, the FALSE condition for the given inequality 3(n−6)<2(n+12) is (D) S:{42}.
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Correct question:
Given the inequality 3(n − 6) < 2(n + 12), determine which integer makes the inequality false.
a. S:{−5}
b. S:{3}
c. S:{12}
d. S:{42}