Question

A 2.5 L flask is filled with 0.25 mol SO3, 0.20 mol SO2, and 0.40 mol O2, and allowed to reach equilibrium. Assume the temperature of the mixture is chosen so that Kc = 0.12. Predict the effect on the concentration of SO3 as equilibrium is achieved by using Q, the reaction quotient.2 SO3(g) 2 SO2(g) + O2(g)

Answer 1

The concentration of SO₃ should decrease as equilibrium is achieved by using Q, the reaction quotient.

Concentration of [SO₃] = 0.25 mol / 2.5L = 0.1M

Concentration of [SO₂] = 0.20 mol / 2.5L = 0.08M

Concentration [O₂] = 0.40 mol / 2.5L = 0.16M

The given equation is

2SO₃ --> 2 SO₂ + O₂

If we put in the concentrations into the equilibrium expression, we get

Q = { [SO2]² x [O2] } divided by [SO3]²

Q = { [0.08M]² x [0.16M]} divided by [0.1M]²

Q = 0.1024

Since Q is less than Kc, as 0.1024 < 012 then reaction should proceed further from left to right in order to achieve equilibrium. Hence, the concentration of SO₃ should decrease as equilibrium is achieved by using Q, the reaction quotient.

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