At noon, ship a is 170 km west of ship b. Ship a is sailing east at 35 km/h and ship b is sailing north at 20 km/h. How fast (in km/hr) is the distance between the ships changing at 4:00 p. M. ? (round your answer to three decimal places. ).

Respuesta :

As of 4:00 p.m., the ships are moving apart at a rapid 31.015km/hr.

What is the name of the ship's speed?

Cruise ships and other maritime vessels measure speed in nautical knots. One nautical mile per hour is one knot.

the separation between ships A and B.

(170–35×4) = 30 We now know that ship a is 30 kilometers west of ship b's original location as of 4 p.m.

20km/hr×4 hr = 80 km. We now know that ship B is located 80 kilometers north of where it was at 4 o'clock.

s²=30²+80²

s²=900+6400

s²=7300

s = 85.44

s =85.44 now the ships are 85.44 km apart at 4 pm.

A right triangle with sides a, b, and c represents the location m of the ships at 4:00 p.m.

a²+b²=c² calculate the derivative:

2a×da/dt+2b×db/dt = 2c×dc/dt

Ship B was 10 kilometers west of the ship's current location at 4 o'clock. Ship B is 80 kilometers north of its starting point at 4 p.m. The ships are 80 kilometers apart as of 4 p.m. The ship travels at a speed of 35 km/hr da/dt. The ship travels at a speed of 20 km/h - db/dt. The result of substituting into the final equation is:

2×30km×35km/hr+2×80km×20km/hr = 2×85.44km×dc/dt

2100km²/hr+3200km²/hr = 170.88km×dc/dt

5300km²/hr= 170.88km×dc/dt

31.015 = dc/dt

dc/dt =31.015km/hr.

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