As of 4:00 p.m., the ships are moving apart at a rapid 31.015km/hr.
Cruise ships and other maritime vessels measure speed in nautical knots. One nautical mile per hour is one knot.
the separation between ships A and B.
(170–35×4) = 30 We now know that ship a is 30 kilometers west of ship b's original location as of 4 p.m.
20km/hr×4 hr = 80 km. We now know that ship B is located 80 kilometers north of where it was at 4 o'clock.
s²=30²+80²
s²=900+6400
s²=7300
s = 85.44
s =85.44 now the ships are 85.44 km apart at 4 pm.
A right triangle with sides a, b, and c represents the location m of the ships at 4:00 p.m.
a²+b²=c² calculate the derivative:
2a×da/dt+2b×db/dt = 2c×dc/dt
Ship B was 10 kilometers west of the ship's current location at 4 o'clock. Ship B is 80 kilometers north of its starting point at 4 p.m. The ships are 80 kilometers apart as of 4 p.m. The ship travels at a speed of 35 km/hr da/dt. The ship travels at a speed of 20 km/h - db/dt. The result of substituting into the final equation is:
2×30km×35km/hr+2×80km×20km/hr = 2×85.44km×dc/dt
2100km²/hr+3200km²/hr = 170.88km×dc/dt
5300km²/hr= 170.88km×dc/dt
31.015 = dc/dt
dc/dt =31.015km/hr.
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