if the focal length of corrective glasses is 48 cm , what is the near point of the eye that the glasses are prescribed for?

Respuesta :

The near point of the eye that the glasses are prescribed for is 16.43 cm.

The formula to be used for calculation is -

[tex] \frac{1}{f} [/tex] = [tex] \frac{1}{v} [/tex] - [tex] \frac{1}{u} [/tex]

The value of u will be 25 cm and we need to calculate v, which is the near point of the eye.

Keep the values in formula -

[tex] \frac{1}{48} [/tex] = [tex] \frac{1}{v} [/tex] - [tex] \frac{1}{25} [/tex]

Rewriting the equation according to v

[tex] \frac{1}{v} [/tex] = [tex] \frac{1}{48} [/tex] + [tex] \frac{1}{25} [/tex]

Performing addition of fractions

[tex] \frac{1}{v} [/tex] = [tex] \frac{25 + 48}{48 × 25} [/tex]

Performing addition in numerator and multiply in denominator on Right Hand Side of the equation

[tex] \frac{1}{v} [/tex] = [tex] \frac{73}{1200} [/tex]

So, the value of v is -

v = 1200/73

Performing division on Right Hand Side of the equation

v = 16.43 cm

Hence, the near point is 16.43 cm.

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