Respuesta :

4Al + 3O2 --> 2Al2O3

(5.23mol Al)(2mol Al2O3/4mol Al) = 2.62mol Al2O3

Answer:

2..615moles of Aluminium oxide

Explanation:

4Al + 3O2 -------> 2Al2O3

(5.23mol Al)×(2molaAl2O3) /(4molAl)

2.615moles of Aluminium oxide

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