Respuesta :
4Al + 3O2 --> 2Al2O3
(5.23mol Al)(2mol Al2O3/4mol Al) = 2.62mol Al2O3
(5.23mol Al)(2mol Al2O3/4mol Al) = 2.62mol Al2O3
Answer:
2..615moles of Aluminium oxide
Explanation:
4Al + 3O2 -------> 2Al2O3
(5.23mol Al)×(2molaAl2O3) /(4molAl)
2.615moles of Aluminium oxide