TR3VZE1
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A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5 m/s.

Circle one: KE / GPE / both

Show your work for finding the values of each type of energy the object has

Respuesta :

Data:
m (mass) = 20 Kg
h (height) = 2 m
s (speed) = 5 m/s
[tex] K_{E} = ?[/tex] kinetic energy (Joule)
GPE (Gravitational potential energy ) = ? (joule)
Both = KE + GPE = ?
Adopting: g (gravity) = 10 m/s²

Solving: (Kinetic Energy)
[tex] K_{E} = \frac{m*s^2}{2} [/tex]
[tex]K_{E} = \frac{20*5^2}{2} [/tex]
[tex]K_{E} = \frac{20*25}{2} [/tex]
[tex]K_{E} = \frac{500}{2} [/tex]
[tex]\boxed{K_{E} = 250\:J}\end{array}}\qquad\quad\checkmark[/tex]

Solving: GPE
[tex]GPE = m*g*h[/tex]
[tex]GPE = 20*10*2[/tex]
[tex]\boxed{GPE = 400\:J}\end{array}}\qquad\quad\checkmark[/tex]

Solving: Both (KE + GPE)
[tex]Both = K_{E} + GPE[/tex]
[tex]Both = 250+400[/tex]
[tex]\boxed{Both = 650\:J}\end{array}}\qquad\quad\checkmark[/tex]



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